I guess route command will give me interface name in last.
To know active interface like eth0, wl0, etc.
#Bash script to get ip address code
The example in the accepted answer takes 337 times longer to process a 5000 line file than the ip-example.sh code in this answer (the other answers on this page should perform similarly to ip-example.h). I am new to shell scripting and trying to create a shell script which will extract and print only ip address from ifconfig command and not all the information. The example code in the accepted answer takes almost 5 times as long to process 5 times more data than to process 1000 lines of data. $ time bash accepted.sh abd.5000 > /dev/null I've seen multiple things online but none of them seem to work. Let's up the ante and test with 5000 lines: $ time sh ip-example.sh abd.5000 > /dev/nullĪbout twice as long to process 5 times more data. Is there a way I can get the IP address of a KVM guest client using bash I need to add this to a bash script to automate a process and part of it is needing to get the IP address of the VM and pass it into a variable. The example in the accepted answer executes in 3 1/2 seconds, about 169 times slower than the 1/40 second in example for this answer. The most easy one was a site that only returned the IP address in plain text and nothing else. It gets that by either using wget -q0 URL or lynx -dump URL. The correct way to grep a variable with on shells that support herestrings is using input redirection with 3 of these guys: <, so your grep command ( $ip variable) should actually read as follows: ip="$(grep -oE '' /dev/null I do have a script that logs the IP address currently in use for the interwebs. I have also heard that backticks are deprecated and should be replaced with $(). Use awk to print the 5th text block for Interface NAME. Use 'ip route get 8.8.8.8 ' to figure out which ACTIVE interface has the route to internet ( or currently being used ) Output should look like : 8.8.4.4 via 10.10.1.1 dev enp0s3 src 10.10.1.118 cache. You can do this with standard system calls. The awk answer is good for your specific case, but the reason you were receiving an error is because you were trying to use grep as if it were searching for a file instead of a variable.Īlso, when using regular expressions, I always use grep -E just to be safe. Here's a small script to solve the problem.
0 kommentar(er)
